What is the Photoelectric Effect?
When a light source (or, more generally, electromagnetic radiation) is incident upon a metallic surface, the surface can emit electrons. Electrons emitted in this fashion are called photoelectrons (although they are still just electrons). This is depicted in the image to the right.
Setting Up the Photoelectric Effect
By administering a negative voltage potential (the black box in the picture) to the collector, it takes more energy for the electrons to complete the journey and initiate the current. The point at which no electrons make it to the collector is called the stopping potential Vs, and can be used to determine the maximum kinetic energy Kmax of the electrons (which have electronic charge e) by using the following equation:
Kmax = eVsIt is significant to note that not all of the electrons will have this energy, but will be emitted with a range of energies based upon the properties of the metal being used. The above equation allows us to calculate the maximum kinetic energy or, in other words, the energy of the particles knocked free of the metal surface with the greatest speed, which will be the trait that is most useful in the rest of this analysis.
The Classical Wave Explanation
Three main predictions come from this classical explanation:
- The intensity of the radiation should have a proportional relationship with the resulting maximum kinetic energy.
- The photoelectric effect should occur for any light, regardless of frequency or wavelength.
- There should be a delay on the order of seconds between the radiation’s contact with the metal and the initial release of photoelectrons.
The Experimental Result
- The intensity of the light source had no effect on the maximum kinetic energy of the photoelectrons.
- Below a certain frequency, the photoelectric effect does not occur at all.
- There is no significant delay (less than 10-9 s) between the light source activation and the emission of the first photoelectrons.
Einstein's Wonderful Year
Building on Max Planck's blackbody radiation theory, Einstein proposed that radiation energy is not continuously distributed over the wavefront, but is instead localized in small bundles (later called photons). The photon's energy would be associated with its frequency (nu), through a proportionality constant known as Planck's constant (h), or alternately, using the wavelength (lambda) and the speed of light (c):
E = h nu = hc / lambdaIn Einstein's theory, a photoelectron releases as a result of an interaction with a single photon, rather than an interaction with the wave as a whole. The energy from that photon transfers instantaneously to a single electron, knocking it free from the metal if the energy (which is, recall, proportional to the frequency nu) is high enough to overcome the work function (phi) of the metal. If the energy (or frequency) is too low, no electrons are knocked free.or the momentum equation: p = h / lambda
If, however, there is excess energy, beyond phi, in the photon, the excess energy is converted into the kinetic energy of the electron:
Kmax = h nu - phiTherefore, Einstein's theory predicts that the maximum kinetic energy is completely independent of the intensity of the light (because it doesn't show up in the equation anywhere). Shining twice as much light results in twice as many photons, and more electrons releasing, but the maximum kinetic energy of those individual electrons won't change unless the energy, not the intensity, of the light changes.
The maximum kinetic energy results when the least-tightly-bound electrons break free, but what about the most-tightly-bound ones; The ones in which there is just enough energy in the photon to knock it loose, but the kinetic energy that results in zero? Setting Kmax equal to zero for this cutoff frequency (nuc), we get:
nuc = phi / hThese equations indicate why a low-frequency light source would be unable to free electrons from the metal, and thus would produce no photoelectrons.or the cutoff wavelength: lambdac = hc / phi
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