Testing Thermal Radiation
If I represents the total intensity of the electromagnetic radiation at all wavelengths, then that intensity over an interval delta-lambda (between the limits of lambda and delta-lamba) is:
delta-I = R(lambda) delta-lambdaR(lambda) is the radiancy, or intensity per unit wavelength interval. In calculus notation, the delta-values reduce to their limit of zero and the equation becomes:
dI = R(lambda) dlambdaThe experiment outlined above detects dI, and therefore R(lambda) can be determined for any desired wavelength.
Radiancy, Temperature, and Wavelength
- The total intensity radiated over all wavelengths (i.e. the area under the R(lambda) curve) increases as the temperature increases.
This is certainly intuitive and, in fact, we find that if we take the integral of the intensity equation above, we obtain a value that is proportional to the fourth power of the temperature. Specifically, the proportionality comes from Stefan’s law and is determined by the Stefan-Boltzmann constant (sigma) in the form:
I = sigma T4
- The value of the wavelength lambdamax at which the radiancy reaches its maximum decreases as the temperature increases.
The experiments show that the maximum wavelength is inversely proportional to the temperature. In fact, we have found that if you multiply lambdamax and the temperature, you obtain a constant, in what is known as Wein’s displacement law:
lambdamax T = 2.898 x 10-3 mK
Blackbody Radiation
Consider a metal box with a small hole in it. If light hits the hole, it will enter the box, and there’s little chance of it bouncing back out. Therefore, in this case, the hole, not the box itself, is the blackbody. The radiation detected outside the hole will be a sample of the radiation inside the box, so some analysis is required to understand what’s happening inside the box.
- The box is filled with electromagnetic standing waves. If the walls are metal, the radiation bounces around inside the box with the electric field stopping at each wall, creating a node at each wall.
- The number of standing waves with wavelengths between lambda and dlambda is
N(lambda) dlambda = (8pi V / lambda4) dlambda
where V is the volume of the box. This can be proven by regular analysis of standing waves and expanding it to three dimensions. - Each individual wave contributes an energy kT to the radiation in the box. From classical thermodynamics, we know that the radiation in the box is in thermal equilibrium with the walls at temperature T. Radiation is absorbed and quickly reemitted by the walls, which creates oscillations in the frequency of the radiation. The mean thermal kinetic energy of an oscillating atom is 0.5kT. Since these are simple harmonic oscillators, the mean kinetic energy is equal to the mean potential energy, so the total energy is kT.
- The radiance is related to the energy density (energy per unit volume) u(lambda) in the relationship
R(lambda) = (c / 4) u(lambda)
This is obtained by determining the amount of radiation passing through an element of surface area within the cavity.
Failure of Classical Physics
Throwing all of this together (i.e. energy density is standing waves per volume times energy per standing wave), we get:u(lambda) = (8pi / lambda4) kTUnfortunately, the Rayleigh-Jeans formula fails horribly to predict the actual results of the experiments. Notice that the radiancy in this equation is inversely proportional to the fourth power of the wavelength, which indicates that at short wavelength (i.e. near 0), the radiancy will approach infinity. (The Rayleigh-Jeans formula is the purple curve in the graph to the right.)R(lambda) = (8pi / lambda4) kT (c / 4) (known as the Rayleigh-Jeans formula)
The data (the other three curves in the graph) actually show a maximum radiancy, and below the lambdamax at this point, the radiancy falls off, approaching 0 as lambda approaches 0.
This failure is called the ultraviolet catastrophe, and by 1900 it had created serious problems for classical physics because it called into question the basic concepts of thermodynamics and electromagnetics that were involved in reaching that equation. (At longer wavelengths, the Rayleigh-Jeans formula is closer to the observed data.)
Planck’s Theory
In 1900, the German physicist Max Planck proposed a bold and innovative resolution to the ultraviolet catastrophe. He reasoned that the problem was that the formula predicted low-wavelength (and, therefore, high-frequency) radiancy much too high. Planck proposed that if there were a way to limit the high-frequency oscillations in the atoms, the corresponding radiancy of high-frequency (again, low-wavelength) waves would also be reduced, which would match the experimental results.Planck suggested that an atom can absorb or reemit energy only in discrete bundles (quanta). If the energy of these quanta are proportional to the radiation frequency, then at large frequencies the energy would similarly become large. Since no standing wave could have an energy greater than kT, this put an effective cap on the high-frequency radiancy, thus solving the ultraviolet catastrophe.
Each oscillator could emit or absorb energy only in quantities that are integer multiples of the quanta of energy (epsilon):
E = n epsilon, where the number of quanta, n = 1, 2, 3, . . .The energy of each quanta is described by the frequency (nu):
epsilon = h nuwhere h is a proportionality constant that came to be known as Planck’s constant. Using this reinterpretation of the nature of energy, Planck found the following (unattractive and scary) equation for the radiancy:
(c / 4)(8pi / lambda4)((hc / lambda)(1 / (ehc/lambda kT – 1)))The average energy kT is replaced by a relationship involving an inverse proportion of the natural exponential e, and Planck’s constant shows up in a couple of places. This correction to the equation, it turns out, fits the data perfectly, even if it isn’t as pretty as the Rayleigh-Jeans formula.
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